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A sample of an ideal gas at 1.00 atm 1.00 atm and a volume of 1.45 L 1.45 L was placed in a weighted balloon and dropped into the ocean. As the sample descended, the water pressure compressed the balloon and reduced its volume. When the pressure had increased to 70.0 atm , 70.0 atm, what was the volume of the sample? Assume that the temperature was held constant.

Respuesta :

Answer:

0.21L

Explanation:

To solve this problem, we make use of Boyle’s law. It states that at constant temperature, the volume of a fixed mass of gas is inversely proportional to its pressure.

Mathematically PV = K

P1V1 = P2V2

P1 = 1 atm

V1 = 1.45L

P2 = 70 atm

v2 = ?

From the equation form, we know that

V2 = P1V1/V2

V2 = ( 1 * 1.45)/70

V2 = 0.021L

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