3) Explain why the standard enthalpy of vaporization, (Delta)Hvap, values for each set of compounds below are not the same.
a. CH4 and H2O
b. PH3 and NH3
c. C2H6 and C3H8
d. BH3 and OF2​

Respuesta :

Answer:

a. CH4 is only held together by London dispersion forces since any dipoles cancel out due to symmetry. On the other hand H2O  has strong hydrogen bonds

b. PH3 has dipole-dipole forces while NH3 is held together by stronger hydrogen bonding

c. C2H6 and C3H8 . Both substances are held together by London dispersion forces since any dipoles cancel out due to symmetry. However C3H8 has the stronger London dispersion forces of the two because it is a larger molecule,

d. BH3 is held together by London dispersion forces since any dipoles cancel out due to symmetry while OF2​ is held together by stronger dipole-dipole forces

The water has more standard enthalpy of vaporization than methane.  [tex]\bold {\Delta V_{vap}}[/tex] is required to vaporize a mole of substance.

What is standard enthalpy of vaporization?

It is the amount of energy that is required to vaporize a mole of substance. It is mainly depends up on inter molecular bonds.

The inter-molecular bond in Methane is only London dispersion forces while the water molecules are held together by hydrogen bonds. Thus the water has more [tex]\bold {\Delta V_{vap}}[/tex].

Therefore, the water has more standard enthalpy of vaporization than methane.

Learn more about inter-molecular bonds.

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