Answer:
Plane dropped 6097 feet in altitude.
Step-by-step explanation:
In the figure attached,
An airplane is at point A from where it continued to descend by 30° for an approximate distance of 2 miles
∠ACB = Angle of descent = 30°
Distance BC = 2 miles
Let the plane dropped the altitude = h miles
Now tan 30° = [tex]\frac{h}{2}[/tex]
[tex]\frac{1}{\sqrt{3}}=\frac{h}{2}[/tex]
[tex]h=\frac{2}{\sqrt{3}}[/tex]
h = 1.155 miles
h ≈ 1.16 miles
Since 1 mile = 5280 feet
1.15 miles = 5280×1.16 feet
= 6097 feet
Therefore, the plane dropped by 6097 feet vertically.
