A chemistry student weighs out of phosphoric acid , a triprotic acid, into a volumetric flask and dilutes to the mark with distilled water. He plans to titrate the acid with solution. Calculate the volume of solution the student will need to add to reach the final equivalence point. Be sure your answer has the correct number of significant digits.

Respuesta :

Answer:

The volume of NaOH solution is 14.8 mL.

Explanation:

the chemical reaction between phosphric acid and sodium hydroxide is as follows.

[tex]H_{3}PO_{4}+3NaOH\rightarrow Na_{3}PO_{4}+3H_{2}O[/tex]

[tex]Moles\,of\,H_{3}PO_{4}= \frac{Mass}{Molarmass\,of\,H_{3}PO_{4}}[/tex]

[tex]= \frac{0.0966}{97.995}=0.00098576mol[/tex]

[tex]Moles\,of\,NaOH=3\times moles\,of\,phosphricacid[/tex]

[tex]Moles\,of\,NaOH=3\times 0.00098576= 0.0029573mol[/tex]

[tex]Volume\,of\,NaOH=\frac{Mole}{Concentration}=\frac{0.0029573}{0.2000}=0.0148L=14.8ml[/tex]

Therefore, The volume of NaOH solution is 14.8 mL.