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Calculate the force required to pull a copper ball of radius 3.50 cm upward through a fluid at the constant speed 6.00 cm/s. Take the drag force to be proportional to the speed, with proportionality constant 0.950 kg/s. Ignore the buoyant force.

Respuesta :

Answer:

F = 15.75 N

Explanation:

given,

radius of copper ball = 3.50 cm = 0.035 m

constant speed = 6 cm/s = 0.06 m/s

proportionality constant = 0.950 Kg/s

mass of the ball

m = ρ V

[tex]V = \dfrac{4}{3}\pi r^3[/tex]

now, net force acting

F = m g + k v

where k is the proportionality constant.

[tex]F = \dfrac{4}{3}\pi r^3 \rho g + k v[/tex]

[tex]F = \dfrac{4}{3}\pi \times 0.035^3(8.92 \times 10^{3})\times 9.8 +0.950 \times 0.06[/tex]

where density of cooper ball = ρ = 8.92 x 10³ kg/m³

       F = 15.75 N