Answer:
Moles of [tex]H_2O[/tex] reacted = 0.1529 moles
Explanation:
Mass of [tex]H_2SO_4[/tex] obtained = 15 g
Thus, formation of the product can be used to determine the moles of water reacted as:-
Molar mass of [tex]H_2SO_4[/tex] = 98.079 g/mol
The formula for the calculation of moles is shown below:
[tex]moles = \frac{Mass\ taken}{Molar\ mass}[/tex]
Thus,
[tex]Moles= \frac{15\ g}{98.079\ g/mol}[/tex]
[tex]Moles_{H_2SO_4}= 0.1529\ mol[/tex]
According to the given reaction:-
[tex]SO_3+H_2O\rightarrow H_2SO_4[/tex]
1 mole of [tex]H_2SO_4[/tex] forms when 1 mole of [tex]H_2O[/tex] is reacted
So,
0.1529 mole of [tex]H_2SO_4[/tex] forms when 0.1529 mole of [tex]H_2O[/tex] is reacted
Thus, Moles of [tex]H_2O[/tex] reacted = 0.1529 moles
