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A sinusoidal electromagnetic wave is propagating in a vacuum in the +z-direction.Part AIf at a particular instant and at a certain point in space the electric field is in the +x-direction and has a magnitude of 4.90 V/m , what is the magnitude of the magnetic field of the wave at this same point in space and instant in time?Part B

What is the direction of the magnetic field?

Respuesta :

Explanation:

Given that,

Magnitude of electric field in +x direction, E = 4.9 V/m

Part A :

The relation between electric and magnetic field is given by :

[tex]B=\dfrac{E}{c}[/tex]

c is the speed of light

[tex]B=\dfrac{4.9\ V/m}{3\times 10^8\ m/s}[/tex]

[tex]B=1.63\times 10^{-8}\ T[/tex]

So, the magnetic field of the wave at this same point in space and instant in time is [tex]1.63\times 10^{-8}\ T[/tex].\

Part B :

The direction of electric and magnetic field is same i.e. +x direction.

Hence, this is the required solution.

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