Answer:
[tex]V=168\pi\ m^3[/tex]
Step-by-step explanation:
we know that
The volume of the figure is equal to the volume of the complete cylinder minus the hollow area.
The volume of a cylinder is equal to
[tex]V=\pi r^{2}h[/tex]
so
The volume of the figure is
[tex]V=\pi r_1^{2}h-\pi r_2^{2}h[/tex]
we have
[tex]r_1=9\ m\\r_2=5\ m\\h=3\ m[/tex]
substitute
[tex]V=\pi (9)^{2}(3)-\pi (5)^{2}(3)[/tex]
[tex]V=168\pi\ m^3[/tex]
