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Suppose a chemical reaction generated a 50% nitrogen/50% oxygen (by volume) mixture of gas that had a total volume of 22.4 liters at STP. How many moles of oxygen does this mixture contain?

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The moles of oxygen in the mixture would be 0.5 moles

Mole calculation

The gas mixture contains 50% oxygen by volume.

Thus: 50/100 of 22.4 L = 12.2 L

This means that the volume of oxygen is 12.2 L.

At STP, 1 mole of any gas equals 22.4 L.

Therefore, 12.2 L of oxygen at STP would be:   12.2 x 1/22.4 = 0.5 moles

More on number of moles of gases can be found here: https://brainly.com/question/11686257

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