Answer:
Step-by-step explanation:
(a)Different 6 -digit PIN's are
Every number from 0 to 9 can be filled in six slots of Pin therefore no of ways are
[tex]=10^{6}[/tex]
(b)No of & digit PIN's are
First number of Pin can be filled in 10 ways
second digit can be filled in 9 ways as repetition is not allowed similarly last digit can be filled with 4 ways
total No of ways are[tex]=10\times 9\times 8\times 7\times 6\times 5\times 4=604800[/tex]