Two metal balls are the same size but one weighs twice as much as the other. The balls are dropped from the roof of a single story building at the same instant of time. The time it takes the balls to reach the ground below will be:

when the balls are released from the top of the store the acceleration of attraction to the floor is gravity and it has a value of 9.8 meters / square second regardless of its weight, all this without counting on air resistance, experiments have been carried out in vacuum rooms where a feather has been dropped and a hammer at the same time, and it is astonishing how they take the same to reach the ground, assuming that there is air as it is in reality, what really can affect the time is the aerodynamics of the object for example if dropping a sheet of paper and a marble.

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snehashish65 snehashish65 · Answer 2 · 2021-10-16T20:03:50+02:00

The time taken by both the metallic balls to reach the ground is same, because the free-fall of balls is independent of the weight.

Given data:

Two same sized metal balls.

Weight of one metal ball = 2 times the weight of another metal ball

The time taken by each metal ball is determined as,

When two objects of similar size dropped from a certain height, they will fall under the influence of gravity with gravitational acceleration (g).
The objects will have no affect of weight to the time taken to reach the ground. However, the time taken by each object is dependent on the density of medium, where object is dropped.

Since, metallic balls are dropped considering the same medium (air), therefore time taken by both balls will be same.

Thus, we can conclude that both the metal balls will take same time to reach the ground due to effect of gravity and same medium (air).

Learn more about free-fall motion here:

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