Answer:
[tex]A = 0.01a^{4}x^{2}[/tex] and [tex]A = - 0.01a^{4}x^{2}[/tex]
[tex]B = \frac{3}{5} a^{n + 2}[/tex] and [tex]B = - \frac{3}{5} a^{n + 2}[/tex]
Step-by-step explanation:
If the square of monomials is given by the given expressions then we have to find the monomials.
Let, [tex]A^{2} = 0.0001 a^{8}x^{4} = (0.01)^{2}(a^{4})^{2}(x^{2} )^{2} = [0.01a^{4}x^{2}]^{2}[/tex]
⇒ [tex]A = 0.01a^{4}x^{2}[/tex] and [tex]A = - 0.01a^{4}x^{2}[/tex]
{Square root both sides}
Again, let [tex]B^{2} = \frac{9}{25}a^{(2n + 4)} = \frac{3^{2} }{5^{2}} a^{2(n + 2)} = [\frac{3}{5}a^{n + 2} ]^{2}[/tex]
⇒ [tex]B = \frac{3}{5} a^{n + 2}[/tex] and [tex]B = - \frac{3}{5} a^{n + 2}[/tex]
{Square root both sides} (Answer)
