Answer:
1. B. Increase
2. A. Decrease
Explanation:
To understand this issue, we need to put some values and using the ohm's law we can corroborate the two situations.
Ohm's law:
[tex]V = I*R\\where:\\I = current[A] ampers\\R = resistance [ohms]\\V = voltage [volts]\\[/tex]
Now for the voltage we will use V = 110 [V], for resistance R = 10 [ohms]
Replacing the values we have:
[tex]I = \frac{V}{R} \\\\I = \frac{110}{10}\\I= 11 [amp][/tex]
Now let's double the voltage 220 [V]:
[tex]I = \frac{220}{10} \\I = 22 [amp]\\[/tex]
Therefore the current will be increased.
Let's do the same for the resistance if originally we have R = 10 [ohms]
[tex]I = \frac{V}{R}\\I = \frac{110}{10} \\I = 11 [amp]\\[/tex]
Now let's double the resistance 20 [ohms]:
[tex]I=\frac{110}{20}\\I = 5.5 [amp][/tex]
Therefore the current will be decreased.
