Answer:
[tex]y-(-3)=-\frac{3}{5}(x-6)[/tex]
Step-by-step explanation:
We are given that the line is passing through the point (1,0) and (6,-3).
We have to find the point- slope equation of the line.
Slope formula:
[tex]m=\frac{y_2-y_1}{x_2-x_1}[/tex]
By using the formula
Slope of the line,[tex]m=\frac{-3-0}{6-1}=-\frac{3}{5}[/tex]
Point- slope equation of line with slope m and passing through the point [tex](x_1,y_1)[/tex] is given by
[tex]y-y_1=m(x-x_1)[/tex]
Using the equation,
The equation of the line passing through the point (6,-3) with slope[tex]-\frac{3}{5}[/tex]
[tex]y-(-3)=-\frac{3}{5}(x-6)[/tex]
This is required equation of the given line.
