Answer:
Kailee bought 26 of 49-cents stamps and 10 of 21-cents stamps.
Step-by-step explanation:
Given:
Total Money paid for stamps = $14.84
Let the number of 49-cents stamps be x.
Also Let the number of 21-cents stamps be y.
Now Total Money paid is equal to sum of number of 49-cents stamps and number of 21-cents stamps.
100 cents = 1$
So 49 cents = $0.49
and 21 cents = $0.21
Hence equation be framed as;
[tex]0.49x+0.21y =14.84 \ \ \ \ equation \ 1[/tex]
Also Given:
number of .49-cents stamps was four less then three times the number of 21-cent stamps.
hence we can say that;
[tex]x=3y-4\ \ \ \ equation \ 2[/tex]
Now Substituting the value of equation 2 in equation 1 we get;
[tex]0.49(3y-4)+0.21y=14.84\\1.47y- 1.96+0.21y=14.84\\1.68y=14.84+1.96\\1.68y = 16.8\\y=\frac{16.8}{1.68}=10[/tex]
Now substituting the value of y in equation 2 we get;
[tex]x=3y-4\\x=3\times10-4\\x=30-4\\x=26\\[/tex]
Hence Kailee bought 26 of 49-cents stamps and 10 of 21-cents stamps.
