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Consider HA2, the intermediate form of a diprotic acid. Ka for this species is 1024 and Kb is 1028 . Nonetheless, the Ka and Kb reac- tions proceed to nearly the same extent when NaHA is dissolved in water. Explain.

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devonmiles84

Answer:

1. naoh + h₂o → na⁺ + oh⁻ + h₂o + heat

2. naoh + hcl → nacl + h₂o

explanation:

1. the dissolving of naoh in water is an exothermic reaction resulting a heat. it also causes the dissociation of naoh to its ions (na⁺ and oh⁻).

so, the balanced equation will be naoh + h₂o → na⁺ + oh⁻ + h₂o + heat.

2. the reaction between acid and base resulting salt and water. it is considered as a neutralization reaction.

the reaction between hcl and naoh will give sodium chloride and water and the balanced equation will be naoh + hcl → nacl + h₂o.

Explanation:

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