[tex]f(x) = \frac{ x^{2} - 4x - 12}{x + 2} [/tex] The point of discontinuity is where the function is undefined; so with a fractional function if the base is zero the the function is undefined thus being the point of discontinuity. [tex] \frac{ (-2)^{2} - 4(-2) - 12}{(-2) + 2} [/tex] = undefined
thus when x is -2 the function would be discontinuous
