Answer:
The other angle is 120°.
Explanation:
Given that,
Angle = 60
Speed = 5.0
We need to calculate the range
Using formula of range
[tex]R=\dfrac{v^2\sin(2\theta)}{g}[/tex]...(I)
The range for the other angle is
[tex]R=\dfrac{v^2\sin(2(\alpha-\theta))}{g}[/tex]....(II)
Here, distance and speed are same
On comparing both range
[tex] \dfrac{v^2\sin(2\theta)}{g}=\dfrac{v^2\sin(2(\alpha-\theta))}{g}[/tex]
[tex]\sin(2\theta)=\sin(2\times(\alpha-\theta))[/tex]
[tex]\sin120=\sin2(\alpha-60)[/tex]
[tex]120=2\alpha-120[/tex]
[tex]\alpha=\dfrac{120+120}{2}[/tex]
[tex]\alpha=120^{\circ}[/tex]
Hence, The other angle is 120°
