Answer:
Jose also has to state that
∠ A ≅∠ A ...............{Reflexive Property}
Step-by-step explanation:
Given:
Jose Shows
[tex]\frac{AE}{AC}= \frac{AD}{AB}[/tex]
TO Prove :
Δ AED ~ Δ ACB by SAS postulate.
Proof:
Jose also has to state that
∠ A ≅∠ A ...............{Reflexive Property}
In Δ AED and Δ ACB
[tex]\frac{AE}{AC}= \frac{AD}{AB}[/tex] ……….{Given}
∠ A ≅ ∠ A …………..{Reflexive Property}
Δ AED ~ Δ ACB ….{ By Side-Angle-Side test}
