Answer:
amount of water produced = 31.76 g of water
Explanation:
20 g of ammonia has [tex]\frac{20}{17}[/tex] moles of ammonia
and 50 g of Oxygen has [tex]\frac{50}{32}[/tex] moles of oxygen .
to find the limiting agent we have to find the mole ratio
mole ratio of ammonia = [tex]\frac{20}{17\times 4}=0.29[/tex]
mole ratio of oxygen = [tex]\frac{50}{32\times 5}=0.31\\[/tex]
therefore the limiting reagent is ammonia.
4 moles ammonia gives 6 moles of water
therefore 1 mole of ammonia gives [tex]\frac{6}{4}[/tex] moles of water
therefore [tex]\frac{20}{17}[/tex] moles of ammonia gives [tex]\frac{6}{4}\times \frac{20}{17}[/tex] moles of water.
amount of water produced = 1.76 moles of water = 31.76 g of water
