Write in slope-intercept form an equation of a line that passes through the given points. (1,6) and (3,2)
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Answer: y = -2x + 8
Step-by-step explanation:
To find the equation of the line , we will use the formula:
[tex]\frac{y_{2}- y_{1}}{x_{2}- x_{1}}[/tex] = [tex]\frac{y-y_{1}}{x - x_{1}}[/tex]
From the question
[tex]x_{1}[/tex] = 1
[tex]x_{2}[/tex] = 3
[tex]y_{1}[/tex] = 6
[tex]y_{2}[/tex] = 2
substituting into the formula , we have
[tex]\frac{2 - 6}{3 - 1}[/tex] = [tex]\frac{y - 6}{x - 1}[/tex]
[tex]\frac{-4}{2}[/tex] = [tex]\frac{y - 6}{x - 1}[/tex]
cross multiplying , we have
2(y-6) = -4(x-1)
Expanding , we have
2y - 12 = -4x + 4
Adding 12 to both sides , we have
2y = -4x + 16
dividing through by 2 , we have
y = -2x + 8
Therefore , the equation of the line is given as
y = -2x + 8