Answer:
Explanation:
Given
[tex]\mu =0.14 Pa.s[/tex]
Volume Flow rate [tex]Q=5.3\times 10^{-5} m^3/s[/tex]
Length [tex]L=37 m[/tex]
radius [tex]r=0.58 cm[/tex]
[tex]D=1.16 cm[/tex]
According to Hagen-Poiseuille Equation
difference in Pressure is given
[tex]\Delta P=\frac{128\mu L\cdot Q}{\pi D^4}[/tex]
[tex]P_{in}-P_{out}=\frac{128\mu L\cdot Q}{\pi D^4}[/tex]
[tex]P_{in}=P_{out}+\frac{128\mu L\cdot Q}{\pi D^4}[/tex]
[tex]P_{in}=1.01325\times 10^5+\frac{128\times 0.14\times 37\times 5.3\times 10^{-5}}{\pi\cdot 1.16^4\times 10^{-8}}[/tex]
[tex]P_{in}=1.01325\times 10^5+6.17\times 10^5[/tex]
[tex]P_{in}=7.19\times 10^5[/tex]
The absolute pressure at the input end is mathematically given as
P=7.19* 10^5
Question Parameter(s):
A pipe is horizontal and carries oil that has a viscosity of 0.14 Pa s
he volume flow rate of the oil is 5.3 × 10-5 m3/s.
and its radius is 0.58 cm.
Generally, the equation for the Pressure change is mathematically given as
[tex]d P=\frac{128\mu L* Q}{\pi D^4}[/tex]
Therefore
[tex]P_{in}=P_{out}+\frac{128\mu L\cdot Q}{\pi D^4}[/tex]
[tex]P_{in}=1.01325\times 10^5+\frac{128\times 0.14\times 37\times 5.3\times 10^{-5}}{\pi\cdot 1.16^4\times 10^{-8}}[/tex]
P=7.19* 10^5
In conclusion, the absolute pressure is
P=7.19* 10^5
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