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I'm not sure how to set up this equation. Aquarium A contains 4.6 gallons of water. Louise will begin filling Aquarium A at a rate of 1.2 gallons per minute.

Aquarium B contains 54.6 gallons of water. Juliet will begin draining Aquarium B at a rate of 0.8 gallons per minute.

After how many minutes will both aquariums contain the same amount of water?

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absor201

After 25 minutes, both Aquariums will contain same amount of water.

Step-by-step explanation:

Given,

Water in Aquarium A = 4.6 gallons

Filling rate = 1.2 gallons per minute.

Let,

x represents the minutes.

A(x) = 4.6 + 1.2x

Because Louise is adding water in the tank.

Water in Aquarium B = 54.6 gallons

Draining rate = 0.8 gallons per minute.

B(x) = 54.6 - 0.8x

Because Juliet is draining water from the tank.

For same amount of water;

A(x) = B(x)

[tex]4.6+1.2x=54.6-0.8x\\1.2x+0.8x=54.6-4.6\\2x=50[/tex]

Dividing both sides by 2

[tex]\frac{2x}{2}=\frac{50}{2}\\x=25[/tex]

After 25 minutes, both Aquariums will contain same amount of water.

Keywords: function, division

Learn more about functions at:

  • brainly.com/question/10772025
  • brainly.com/question/10879401

#LearnwithBrainly

Answer:C. 25 mins

Step-by-step explanation:

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