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In the following reaction, how many grams of oxygen will react with 10.47 grams of benzene (C6H6)? 2C6H6 + 15O2 12CO2 + 6H2O The molar mass of benzene is 78.1074 grams and that of O2 is 32 grams.

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The balanced chemical reaction will be:

2C6H6 + 15O2 = 12CO2 + 6H2O

We are given the amount of benzene to react with oxygen gas. This will be our starting point.

 

10.47 g C6H6 ( 1 mol C6H6 / 78.1074 grams C6H6) (15 mol O2/2 mol C6H6 ) ( 32 g O2 / 1 mol O2) =  32.1711g O2

Answer:

32.171087  grams of oxygen will react with 10.47 grams of benzene.

Explanation:

[tex]2C_6H_6 + 15O_2\rightarrow 12CO_2 + 6H_2O[/tex]

Moles of benzene = [tex]\frac{10.47 g}{78.1074 g/mol}=0.1340462 mol[/tex]

According to reaction ,2 moles of benzene reacts with 15 moles of oxygen

Then 0.1340462 moles of benzene will react with:

[tex]\frac{15}{2}\times 0.1340462 mol=1.0053464 mol[/tex] of oxygen

Mass of 1.0053464 moles of oxygen ;

[tex]1.0053464 mol\times 32=32.171087 g[/tex]

32.171087  grams of oxygen will react with 10.47 grams of benzene.

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