Respuesta :
Answer:
Gd → Gd⁺ + 1e⁻, Gd⁺ → Gd⁺² + 1e⁻, Gd⁺² → Gd⁺³ + 1e⁻
Explanation:
The ionization energy is the energy necessary to remove one electron of the atom, transforming it in a cation. The first ionization energy is the energy necessary to remove the first electron, the second energy, to remove the second electron, and then successively.
Thus, for gadolinium (Gd)
Fisrt ionization:
Gd → Gd⁺ + 1e⁻
Second ionization:
Gd⁺ → Gd⁺² + 1e⁻
Third ionization:
Gd⁺² → Gd⁺³ + 1e⁻
The equations that show the processes that describe the first, second, and third ionization energies for a gaseous gadolinium atom are as follows;
- Gd ==> Gd+ + e-. 1st ionization energy, H1
- Gd+ ==> Gd²+ + e- 2nd ionization energy, H2
- Gd²+ ==> Gd³+ + e-. 3rd ionization energy, H3
The ionization energy of an atom is the quantity of energy required to completely remove an electron from the outermost shell of the atom.
In essence;
- The First Ionization Energy of the Gd atom is the quantity of energy required to completely remove its first Valence electron so that it takes up a +1 charge
- The Second Ionization Energy of the Gd atom is the quantity of energy required to completely remove its second Valence electron so that it takes up a +2 charge
- The Third Ionization Energy of the Gd atom is the quantity of energy required to completely remove its third Valence electron so that it takes up a +3 charge
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