Write equations that show the processes that describe the first, second, and third ionization energies for a gaseous gadolinium atom. Express your answers as chemical equations separated by commas.

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Answer:

Gd → Gd⁺ + 1e⁻, Gd⁺ → Gd⁺² + 1e⁻, Gd⁺² → Gd⁺³ + 1e⁻

Explanation:

The ionization energy is the energy necessary to remove one electron of the atom, transforming it in a cation. The first ionization energy is the energy necessary to remove the first electron, the second energy, to remove the second electron, and then successively.

Thus, for gadolinium (Gd)

Fisrt ionization:

Gd → Gd⁺ + 1e⁻

Second ionization:

Gd⁺ → Gd⁺² + 1e⁻

Third ionization:

Gd⁺² → Gd⁺³ + 1e⁻

The equations that show the processes that describe the first, second, and third ionization energies for a gaseous gadolinium atom are as follows;

  • Gd ==> Gd+ + e-. 1st ionization energy, H1

  • Gd+ ==> Gd²+ + e- 2nd ionization energy, H2

  • Gd²+ ==> Gd³+ + e-. 3rd ionization energy, H3

The ionization energy of an atom is the quantity of energy required to completely remove an electron from the outermost shell of the atom.

In essence;

  • The First Ionization Energy of the Gd atom is the quantity of energy required to completely remove its first Valence electron so that it takes up a +1 charge

  • The Second Ionization Energy of the Gd atom is the quantity of energy required to completely remove its second Valence electron so that it takes up a +2 charge

  • The Third Ionization Energy of the Gd atom is the quantity of energy required to completely remove its third Valence electron so that it takes up a +3 charge

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