Answer:
If the force is perpendicular to the wrench, and If we use a wrench that is 0.2m long, then [tex]F=230N[/tex]
Explanation:
As there is no draw in the question, we can imagine the spark plug being in a point were the wrench starts, and the force being exerted where the wrench ends. As the torque is a vectorial quantity, we imagine the force being exerted in a direction perpendicular to the wrench, and the wrench with a longitude l. The definition of torque is
[tex]\tau=l*F*sen\theta[/tex]
and as we exerted the force perpendicular to the wrench, θ is 90°, so sen(90°) is equal to 1. Then
[tex]\tau=l*F[/tex]
Now, if the wrench is 0.2 m long, then
[tex]F=\frac{46Nm}{0.2m}=230N[/tex] is the magnitude F of the force exerted to get 46 Nm of torque.
