The total length is 226.59 units. The flagpole is at (78,75)
Step-by-step explanation:
To find the distance between two points given the coordinates apply the formula for distance as;
[tex]d=\sqrt{(y_2-y_1)^2+ (x_2-x_1)^2}[/tex]
For segment ;
AB, A(-20,60) and B(-20,-25)
[tex]d=\sqrt{(-25-60)^2} \\\\d=\sqrt{(-85)^2} \\\\d=85[/tex]
For segment AD
A(-20,60) and D(50,75)
[tex]d=\sqrt{(75-60)^2+(50--20)^2} \\\\d=\sqrt{(15)^2+(70)^2} \\\\d=\sqrt{5125} \\\\d=71.59[/tex]
For segment
BC
B(-20,-25) and C(50,-25)
[tex]d=\sqrt{(50--20)^2} \\\\d=\sqrt{70^2} \\\\d=70[/tex]
Total length of the three hallways is 85+71.59+70 =226.59 units
PART B
The flagpole is 28 meters to the right of point D
Point D(50,75)
Flagpole will be (50+28,75), = (78,75)
Learn More
To find length of a segments using coordinates :https://brainly.com/question/13502098
Keywords :coordinate plane, plot, clockwise
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