A balloon containing 0.10 moles of gas has a volume of 2.00 liters. If temperature and pressure remain constant, the new volume will be 3.00 liters when you add 0.15 moles of gas to the balloon.
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Answer:

In a balloon with a volume of 3.00 L gas, there is a total of 0.15 moles of gas.

If we add 0.15 moles to a balloon containing 0.10 moles, the new volume is 5 L

Explanation:

Step 1: Data given

Number of moles = 0.10 moles of gas

Volume of gas= 2.00 L

New volume = 3.00 L

Step 2: Calculate new number of moles

Avogadro's law says:

n1/V1 = n2/V2

⇒ with n1 = the number of moles of gas = 0.10 moles

⇒ with V1 = the volume of gas in the balloon = 2.00 L

⇒ with n2 = the number of moles when then volume changed to 3.00L

⇒ with V2 = the new volume = 3.00 L

0.10 mol / 2.00 L = n2 / 3.00 L

n2 = (0.10 * 3.00)/2.00

n2 = 0.15 moles

When adding 0.15 moles of gas to the balloon, the total number of moles is 0.25 moles, the total volume will be:

0.10 mol / 2.00 L = 0.25 moles / V2

V2 = 5 L

In a balloon with a volume of 3.00 L gas, there is a total of 0.15 moles of gas.

If we add 0.15 moles to a balloon containing 0.10 moles, the new volume is 5 L