Answer:
The speed of ping pong ball is 160.35 m/s
Explanation:
Given that,
Mass of the bowling ball, [tex]m_1=7\ kg[/tex]
Speed of mass 1, [tex]v_1=3\ m/s[/tex]
Mass of ping pong ball, [tex]m_2=2.45\ g=2.45\times 10^{-3}\ kg[/tex]
The kinetic energy of a body is given by:
[tex]K=\dfrac{1}{2}mv^2[/tex]
According to given condition, the two balls have the same kinetic energy
[tex]K_1=K_2[/tex]
[tex]\dfrac{1}{2}m_1v_1^2=\dfrac{1}{2}m_2v_2^2[/tex]
[tex]m_1v_1^2=m_2v_2^2[/tex]
[tex]v_2[/tex] is the speed of ping pong ball
[tex]v_2=\sqrt{\dfrac{m_1v_1^2}{m_2}}[/tex]
[tex]v_2=\sqrt{\dfrac{7\times (3)^2}{2.45\times 10^{-3}}}[/tex]
[tex]v_2=160.35\ m/s[/tex]
So, the speed of ping pong ball is 160.35 m/s. Hence, this is the required solution.
