Answer:
5.192
Explanation:
This is a two tailed test hence the null and alternative hypothesis will be
[tex]H_o: P=0.5[/tex]
[tex]H_a: P>0.5[/tex]
Sample size, n=674
Sample proportion [tex]\bar p=0.60[/tex]
Z test statistic formula for one sample is given by
[tex]Z=\frac {\bar p-P}{\sqrt{\frac {P\times(1-P)}{n}}}[/tex]
Substituting the values given then
[tex]Z=\frac {0.6-0.5}{\sqrt{\frac {0.5\times (1-0.5)}{674}}}=5.192302\approx 5.192[/tex]
