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An animal shelter spends $3.50 per day to care for each cat and $7.00 per day to care for each dog. Isaac noticed that the shelter spent $157.50 caring for cats and dogs on Thursday. Isaac found a record showing that there were a total of 28 cats and dogs on Thursday. How many cats were at the shelter on Thursday?

Respuesta :

absor201

There were 11 cats at the shelter on Thursday.

Step-by-step explanation:

Amount spent on one cat = $3.50

Amount spent on one dog = $7.00

Total spent on Thursday = $157.50

Total animals cared = 28

Let,

Number of cats = x

Number of dogs = y

According to given statement;

x+y=28    Eqn 1

3.50+7.00y=157.50    Eqn 2

Multiplying Eqn 1 by 7 in order to eliminate y

[tex]7(x+y=28)\\7x+7y=196\ \ \ Eqn\ 3[/tex]

Subtracting Eqn 2 from Eqn 3

[tex](7x+7y)-(3.50x+7.00y)=196-157.50\\7x+7y-3.50x-7.00y=38.50\\3.50x=38.50[/tex]

Dividing both sides by 3.50

[tex]\frac{3.50x}{3.50}=\frac{38.50}{3.50}\\x=11[/tex]

There were 11 cats at the shelter on Thursday.

Keywords: linear equation, subtraction

Learn more about linear equations at:

  • brainly.com/question/8799684
  • brainly.com/question/8805387

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