Answer:
Therefore,the required factors are ( x - 16 ) and ( x + 3 )is
Step-by-step explanation:
Given:
[tex]x^{2} -13x-48[/tex]
To Factorize:
Solution:
First remove the factor of -48 such that you multiply the two number, the Product should be -48 and the SUM should be -13.
-48 = -16 × 3
Here, -16 and 3 are the two required numbers
now the given expression we will split the middle term and Factorize the given equation.
[tex]x^{2} -13x-48 =x^{2} -16x+3x-48\\\\\\\textrm{removing x common and 3 common we get}\\x^{2} -13x-48=x(x-16)+3(x-16)\\\\x^{2} -13x-48=(x-16)(x-3)[/tex]
Therefore,the required factors are ( x - 16 ) and ( x + 3 )
