Tiny water droplets in the air disperse the white light of the sun into a rainbow. What is the energy of a photon from the
red portion of the rainbow if it has a frequency of 4.57 x 10s??​

Respuesta :

Answer:

3.03 x 10⁻³² J

Explanation:

Data Given

Frequency of the light = 4.57 x 10 s⁻¹

Energy of the photon

Solution

Formula used

           E = hν

where

E = energy of photon

h = Planck's Constant

Planck's Constant = 6.626 x 10⁻³⁴ Js

ν = frequency

Put values in above equation

    E = hν

     E = 6.626 x 10⁻³⁴ Js x 4.57 x 10 s⁻¹

     E = 3.03 x 10⁻³² J