Answer:
Part 1) The area of the square is 20 square units
Part 2) The area of the square is 12 square units
Step-by-step explanation:
In this problem we have two cases
Part 1) The third side of the right triangle is the hypotenuse
so
we have
[tex]a=2\ units\\b=4\ units[/tex]
c is the hypotenuse (third side)
The area of the square is equal to length of the third side squared
Applying Pythagorean Theorem
[tex]c^2=a^2+b^2[/tex]
substitute the given values
[tex]c^2=2^2+4^2[/tex]
[tex]c^2=20\ units^2[/tex]
The area of the square is 20 square units
Part 2) The third side of the right triangle is a leg
so
we have
[tex]a=2\ units\\c=4\ units[/tex]
b is a leg (third side)
The area of the square is equal to length of the third side squared
Applying Pythagorean Theorem
[tex]c^2=a^2+b^2[/tex]
substitute the given values
[tex]4^2=2^2+b^2[/tex]
[tex]b^2=16-4=12\ units^2[/tex]
The area of the square is 12 square units
Answer: 20units
Step-by-step explanation:
The person on top of me said it wrong and I got it wrong hope u don’t get it wrong
