Answer:
The area of the figure ABCD is [tex]25\ units^{2}[/tex]
Step-by-step explanation:
we have
[tex]A(-3, 2), B(2, 2), C(2, -4), D(-3, -2)[/tex]
using a graphing tool
Plot the figure
see the attached figure
The figure is a trapezoid
The area of the trapezoid is equal to
[tex]A=\frac{1}{2}(AD+BC)AB[/tex]
Find the distance between the points in the graph
we have
[tex]AD=4\ units[/tex]
[tex]BC=6\ units[/tex]
[tex]AB=5\ units[/tex]
substitute
[tex]A=\frac{1}{2}(4+6)5=25\ units^{2}[/tex]
