The equation of the line in point-slope form that passes through the points (x, y) = (0, 2) and (x, y) = (3, 1) is [tex](y-1)=-1(x-3)[/tex]
Step-by-step explanation:
We need to Write an equation of the line in point-slope form that passes through the points
(x, y) = (0, 2) and (x, y) = (3, 1).
The standard form of point-slope is:
[tex](y-y_1)=m(x-x_1)[/tex]
where m is slope.
Finding slope first:
The formula used to find slope is:
[tex]Slope=\frac{y_2-y_1}{x_2-x_1}[/tex]
where [tex]x_1=3,y_1=1,x_2=0,y_2=2[/tex]
Putting values and finding slope:
[tex]Slope=\frac{y_2-y_1}{x_2-x_1}[/tex]
[tex]Slope=\frac{2-1}{0-1}[/tex]
[tex]Slope=\frac{1}{-1}[/tex]
[tex]Slope=-1[/tex]
Now finding equation in point-slope form using point (3,1)
[tex](y-y_1)=m(x-x_1)[/tex]
[tex](y-1)=-1(x-3)[/tex]
So, the equation of the line in point-slope form that passes through the points (x, y) = (0, 2) and (x, y) = (3, 1) is [tex](y-1)=-1(x-3)[/tex]
Keywords: Point-Slope form
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