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Suppose the given data was collected on five populations of cattle. Breed DD Dd dd Shorthorn 0.36 0.48 0.16 Braunvien 0.09 0.42 0.49 Texas Longhorn 0.16 0.53 0.31 Murray Grey 0.23 0.63 0.14 Mongolian 0.20 0.58 0.22 Which of the populations are in Hardy–Weinberg equilibrium?

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Answer:

Shorthorn 0.36 0.48 0.16 is the only cattle population in Hardy–Weinberg equilibrium

Explanation:

We know that the frequency of the recessive homozygote genotype "dd" is q2 and equal to 0.16

Obtain the square root of q2

square root of 0.16 = 0.4

AND we also know that p + q = 1

Thus, p = 1 – q ∴ p = 1 – 0.4 = 0.6

∴The homozygote dominant "DD" is represented by p2;

The square of p is obtained below

(0.6)2 = 0.36

Note that of all the cattle population, Shorthorn 0.36 0.48 0.16 has its "dd" and "DD" traits obey the pattern shown above

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