It takes 155. kJ/mol to break a fluorine-fluorine single bond. Calculate the maximum wavelength of light for which a fluorine-fluorine single bond could be broken by absorbing a single photon. Be sure your answer has the correct number of significant digits.

Respuesta :

Answer:

1.3*10^-30m

Explanation:

The energy of the bond= energy of the photon.

E=hf f=E/h= 155*10^3/6.6*10^-34= 23.5*10^37 Hz

But V=wavelength* frequency

Wavelength= 3*10^8/23.5*10^37 = 1.3*10^-30 m

Note, speed of a photon of light= 3*10^8 ms-1

Answer:

772 nanometers.

Explanation:

The maximum wavelength of light corresponds to minimum energy required to break one mole of flourine-flourine single bond which is 155 kJ.

Energy required to break one F-F bond is [tex]\frac{155}{6.023 \times 10^{23} }[/tex] kJ.

Energy of photon is given by:

E=\frac{nhc}{\lambda}[/tex]

where

n = number of photons h=[tex]6.626 \times 10^{-34}[/tex]Js and [tex]\lambda[/tex]=wavelength of photon and c=[tex]3 \times 10^{8}[/tex][tex]\frac{m}{s}[/tex]

In this question E=[tex]\frac{155 \times 10^{3}}{6.023 \times 10^{23} }[/tex]

and n=1

Substituting appropriate values in the above equation, we get:

[tex]\lambda=0.77242\times 10^{-6}[/tex] metres

                    =772.42 nanometers

                    =772 nanometers as value given in the question has 3 significant digits.