Answer:
a. [tex]X^BY[/tex]
b. [tex]X^BX^B[/tex]
c. [tex]X^{b} Y[/tex]
d. [tex]X^BX^b[/tex]
e. [tex]X^bX^b[/tex]
Explanation:
There are two sex chromosomes, X and Y. A female has two X chromosomes and the male has an X and a Y. The genotype then for male and female woud be:
Female = XX
Male = XY
Now the superscript indicates the allele for a particular trait.
Based on what was given:
H is dominant (no hemophilia)
h is recessive (hemophilic)
B is dominant (no color blindness)
b is recessive (color blind)
As you can see in the given, the Y chromosome has no allele, this means that hemophilia and color-blindness is X-linked or dependent on the X chromosome.
For the first, it says normal male this means that the genotype would be XY , the X chromosome would have the normal dominant allele for color-blindness so that would be B.
[tex]X^BY[/tex]
The next one would be homozygous normal female. This means that the female has both dominant alleles on their chromosome (BB)
[tex]X^BX^B[/tex]
The third one says colorblind male. Unlike the females, the male chromosomes only need the X to be affected for them to express the trait. So in this case, the X will have the recessive allele for colorblindness (b).
[tex]X^{b} Y[/tex]
The foruth one is a normal female for color-blindess but is heterozygous. This means that the female has the recessive allele, but the dominant trait masks it. So it will have both alleles (Bb)
[tex]X^BX^b[/tex]
Lastly, a color-blind female would have to have two recessive alleles. This is what we call homozygous recessive (bb).
[tex]X^bX^b[/tex]
