Answer:
S(filament) = 2.5 W/K, S(heater/room) = -9.257 W/K, S(air/outside) = 0.386 W/K
Explanation:
Room air temperature T(l) = 296K
Filament Temperature T₂ = 800 K
Heat pump, Q = -2000W
Outside Temperature, T₃ = 7° C = 280 K
Use the relation of entropy to heat to find out the entropy generation at each interface
[S(generated)(1 to 2)]filament = -∫dQ/T
At filament
S = - (-2000)/800
S = 2000/800 = 2.5 W/K
At the space between the heater and the room
S(heater to room) = - ∫dQ/T
S(heater to room) = (-2000/800) – (2000/296)
S(heater to room) = -9.257W/K
At wall between air and outside
S(air to outside) = - ∫dQ/T
S(air to outside) = (-2000/296) + (2000/280)
S(air to outside) = 0.386 W/K