Answer:
Explanation:
Electric force between two particles
= ( 9x10⁹x7.4 x 10⁻⁶ x 3.2 x 10⁻⁶ )/ (3.2 x 10⁻²)² ( Distance between particles is 1.6 +1.6 = 3.2 cm . )
= 20.81 x 10 = 208.1 N
1 ) Magnetic field due to movement of second charge
= [tex]\frac{\mu_0}{4\pi} \frac{qv}{r^2 }[/tex]
= 10⁻⁷ x 3.2 x 10⁻⁶ x 4 / (3.2 x 10⁻²)²
B = 1.25 x 10⁻⁹ T.
Due to this magnetic field , there is a force called magnetic force on first particle which will be expressed as follows
Force = Bqv
= 1.25 x 10⁻⁹ x 7.4 x 10⁻⁶ x 4
37 x 10⁻¹⁵ N
2 ) For magnetic force to be equal to electric force let velocity o particles be V
Then magnetic field due to second charge
= 10⁻⁷ x 3.2 x 10⁻⁶ x v / (3.2 x 10⁻²)²
= .3125 v x 10⁻⁹
Magnetic force on first charge
Bqv
= .3125 v x 10⁻⁹ x 7.4 x 10⁻⁶ x v
2.3125 x 10⁻¹⁵ v²
magnetic force = electric force
2.3125 x 10⁻¹⁵ v² = 208.1
v² = 90 x 10¹⁵
v² = 900 x 10¹⁴
v = 30 x 10⁷ m /s
