Respuesta :
Answer:
[tex]\frac{5280mt}{12p}[/tex]
Explanation:
Given,
Length of the highway = m miles = 5280m feet ( ∵ 1 mile = 5280 ft ),
It width = t inches = [tex]\frac{t}{12}[/tex] feet ( ∵ 1 feet = 12 inches ⇒ 1 inch = 1/12 feet )
Thus, the area of the highway,
[tex]A=length\times width[/tex]
[tex]=5280m\times \frac{t}{12}[/tex]
[tex]=\frac{5280mt}{12}\text{ square feet}[/tex]
Since,
Paint required for p ft² area = 1 gallon,
Paint required for 1 ft² area = 1/p gallon,
∴ Paint required for [tex]\frac{5280mt}{12}[/tex] ft² area = [tex]\frac{5280mt}{12p}[/tex] gallon,
Hence, the number of gallon of paint required is [tex]\frac{5280mt}{12p}[/tex]
Answer:
A solid yellow stripe is to be painted in the middle of a certain highway. If 1 gallon of paint covers an area of p square feet of highway, how many gallons of paint will be needed to paint a stripe t inches wide on a stretch of highway m miles long? (1 mile = 5,280 feet and 1 foot = 12 inches) \small \frac{5,280mt}{12p} \small \frac{5,280pt}{12m} \small \frac{5,280pmt}{12} \small \frac{(5,280)(12m)}{pt} \small \frac{(5,280)(12p)}{mt} Next Previous HelpEnd Review Review Screen
Explanation:
