Answer:
Explanation:
Given
mass of each railroad is M
first railroad is moving with velocity [tex]v_1[/tex] and other two's with [tex]v_2[/tex]
conserving Momentum
[tex]Mv_1+2Mv_2=3M v_f[/tex]
where v_f is the final velocity of combined system
[tex]v_f=\frac{v_1+2v_2}{3}[/tex]
(b)Initial Kinetic Energy
[tex]=\frac{1}{2}Mv_1^2+\frac{1}{2}2Mv_2^2[/tex]
[tex]=\frac{1}{2}Mv_1^2+Mv_2^2[/tex]
Final Kinetic Energy
[tex]=\frac{1}{2}3Mv_f^2=\frac{1}{6}M(v_1^2+4v_2^{2}+4v_{1}v_2)[/tex]
Loss in Kinetic Energy
[tex]=\frac{1}{2}Mv_1^2+Mv_2^2-\frac{1}{6}M(v_1^2+4v_2^{2}+4v_{1}v_2)[/tex]
[tex]=M(v_1-v_2^2)^2[/tex]
