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Miriam reduced a square photo by cutting 3 inches from each side so it will fit in her photo album. The area of the reduced photo is 64 square inches. In the equation
(x – 3)2 = 64, x represents the side measure of the original photo.

What were the dimensions of the original photo?

A.11 inches by 11 inches
B.5 inches by 5 inches
C.3 + inches by 3 + inches
D.3 inches by 3 inches

Respuesta :

jhonyy9
(x-3)^2 =64

(x-3)^2 =8^2

x-3 =8

x = 11 so from this result choice A. is right sure 

Answer:

A. 11 inches by 11 inches

Step-by-step explanation:

Here, the given equation,

[tex](x-3)^2=64[/tex]

Where x represents the side of the original photo,

[tex]x-3=\pm 8[/tex]

If x - 3 = 8 ⇒ x = 11.

If x - 3 = -8 ⇒ x = -5,

Since, the side can not be negative,

Thus, the side of the original figure is 11 inches,

Also, the photo is square shaped ( quadrilateral having equal sides ),

Hence, the dimension of the original photo is,

11 inches × 11 inches,

= 11 inches by 11 inches.

Option A is correct.

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