Answer:
the smallest angle from the antennas is 47.3°
Explanation:
We first need to write the expression for the relation between the wavelength (λ) and the frequency (f) of the wave, and then solve for the wavelength.
Therefore, the relation is:
λ = c /f
where
Thus,
λ = (3 × 10⁸ m/s) / (3.4 MHz)
= (3 × 10⁸ m/s) / (3.4 MHz)(10⁶ Hz/1 MHz)
= 88.235 m
Therefore, the smallest angle measured (from the north of east) from the antennas for the constructive interference of the two-radio wave can be calculated as
θ = sin⁻¹(λ / d)
where
Thus,
θ = sin⁻¹(88.235 / 120)
θ = 47.3 °
Therefore, the smallest angle from the antennas, measured north of east, at which constructive interference of two radio waves occurs is 47.3 °.
