Answer:
t = 5.55 mm
Explanation:
given,
Gauge pressure (P)=640 kpa
Allowable normal stress =150 Mpa.
Inner diameter of tank =2.6 m.
Minimum thickness of wall. = ?
In case of closed cylinders there are two cases.
one is Circumferential stress and another one is longitudinal stress.
According to circumferential stress
[tex]\sigma =\dfrac{pd}{2t}[/tex]
Where
p=pressure, d=diameter, t= thickness,
by substituting all values we get,
[tex]t=\dfrac{pd}{2\sigma }[/tex]
[tex]t=\dfrac{640\times 10^3\times 2.6}{2\times 150\times 10^{6}}[/tex]
t = 5.55 mm
minimum thickness of the wall is equal to t = 5.55 mm
