Answer:
density = 5520 kg/m^3
Explanation:
given that
radius of earth = 6378 km
G = 6.67 x 10⁻¹¹ m³/kg.s²
g = 9.80 m/s²
we know,
[tex]g = \dfrac{GM}{r^2}[/tex]
mass of earth
[tex]M = \dfrac{gr^2}{G}[/tex]
[tex]M = \dfrac{9.8 \times (6378 \times 10^3)^2}{6.67 \times 10^{-11}}[/tex]
M = 5.972 x 10²⁴ kg
density =[tex]\dfrac{mass}{volume}[/tex]
V = volume of the earth = 4/3πr³
V = 4/3 x 3.14 x (6378 x 10³)³
V = 1.08 x 10²¹ m³
density = [tex]\dfrac{5.972\times 10^{24}}{1.08\times 10^{21}}[/tex]
density = 5.52 x 10³ kg/m^3
density = 5520 kg/m^3
