Answer:
Explanation:
Given
Mass of man [tex]m=83 kg[/tex]
density [tex]\rho =996 kg/m^3[/tex]
volume [tex]V=\frac{m}{\rho }[/tex]
[tex]V=\frac{83}{996}=0.0833 m^3[/tex]
(b)Buoyant Force by Air
[tex]\rho _{air}=1.29 kg/m^3[/tex]
[tex]F_b=\rho _{air}Vg[/tex]
[tex]F_b=1.29\times 0.0833\times 9.8[/tex]
[tex]F_b=1.053 N[/tex]
(c)Ratio of the buoyant Force to his weight
[tex]=\frac{F_b}{Weight}[/tex]
Weight=mg
[tex]weight=83\times 9.8=813.4 N[/tex]
[tex]Ratio=\frac{1.053}{813.4}=0.00129[/tex]
