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A sample of ammonia gas at 65.5°C and 524 torr has a volume of 15.31 L. What is its volume when the temperature is –15.8°C and its pressure is 524 torr? 20.2 L 11.6 L 63.5 L not possible, since the volume would have to be negative 3.69 L

Respuesta :

shakha2017

P=const

T=65.5+273=338.5°K

T₁=273-15.8=257.2°K

V/T=V₁/T₁

V₁=VT₁/T=

[tex] = \frac{15.31 \times 257.2}{338.5} = 11.6 \: l[/tex]

raphealnwobi

The volume when the temperature is –15.8°C and its pressure is 524 torr is 11.6 L

The combined gas law is given by:

[tex]\frac{P_1V_1}{T_1} =\frac{P_2V_2}{T_2}[/tex]

T₁ = initial temperature = 65.5°C = 15.8 + 273.15 = 338.65K, P₁ is initial pressure = 524 torr, V₁ is initial volume = 15.31 L, T₂ is final temperature = -15.8°C = -15.8 + 273.15 = 257.35K, P₂ is final pressure = 524 torr

Hence:

[tex]\frac{524*15.31}{338.65}= \frac{524*V_2}{257.35} \\\\V_2=11.6\ L[/tex]

The volume when the temperature is –15.8°C and its pressure is 524 torr is 11.6 L

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