Answer:
Explanation:
Given
Temperature of Hot reservoir [tex]T_1=400 K[/tex]
Temperature of Cold reservoir [tex]T_2=300 K[/tex]
Heat reservoir [tex]Q=500 J[/tex]
Work done [tex]W=150 J[/tex]
heat Exhaust [tex]Q_{rejection }=350 J[/tex]
[tex]Q=W+Q_{rejected}[/tex]
[tex]500=150+350[/tex]
L.H.S=R.H.S
thus it follows first law
[tex]\eta _{carnot}=1-\frac{T_L}{T_H}[/tex]
[tex]\eta _{carnot}=1-\frac{300}{400}[/tex]
[tex]\eta _{carnot}=0.25[/tex]
Cycle Efficiency
[tex]\eta =\frac{W}{Q}=\frac{150}{500}=0.3[/tex]
Carnot efficiency is less than cycle thus it violates second law
